.5y^2+2y-1=0

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Solution for .5y^2+2y-1=0 equation:


Simplifying
0.5y2 + 2y + -1 = 0

Reorder the terms:
-1 + 2y + 0.5y2 = 0

Solving
-1 + 2y + 0.5y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
0.5 the coefficient of the squared term: 

Divide each side by '0.5'.
-2 + 4y + y2 = 0

Move the constant term to the right:

Add '2' to each side of the equation.
-2 + 4y + 2 + y2 = 0 + 2

Reorder the terms:
-2 + 2 + 4y + y2 = 0 + 2

Combine like terms: -2 + 2 = 0
0 + 4y + y2 = 0 + 2
4y + y2 = 0 + 2

Combine like terms: 0 + 2 = 2
4y + y2 = 2

The y term is 4y.  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
4y + 4 + y2 = 2 + 4

Reorder the terms:
4 + 4y + y2 = 2 + 4

Combine like terms: 2 + 4 = 6
4 + 4y + y2 = 6

Factor a perfect square on the left side:
(y + 2)(y + 2) = 6

Calculate the square root of the right side: 2.449489743

Break this problem into two subproblems by setting 
(y + 2) equal to 2.449489743 and -2.449489743.

Subproblem 1

y + 2 = 2.449489743 Simplifying y + 2 = 2.449489743 Reorder the terms: 2 + y = 2.449489743 Solving 2 + y = 2.449489743 Solving for variable 'y'. Move all terms containing y to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + y = 2.449489743 + -2 Combine like terms: 2 + -2 = 0 0 + y = 2.449489743 + -2 y = 2.449489743 + -2 Combine like terms: 2.449489743 + -2 = 0.449489743 y = 0.449489743 Simplifying y = 0.449489743

Subproblem 2

y + 2 = -2.449489743 Simplifying y + 2 = -2.449489743 Reorder the terms: 2 + y = -2.449489743 Solving 2 + y = -2.449489743 Solving for variable 'y'. Move all terms containing y to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + y = -2.449489743 + -2 Combine like terms: 2 + -2 = 0 0 + y = -2.449489743 + -2 y = -2.449489743 + -2 Combine like terms: -2.449489743 + -2 = -4.449489743 y = -4.449489743 Simplifying y = -4.449489743

Solution

The solution to the problem is based on the solutions from the subproblems. y = {0.449489743, -4.449489743}

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